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Photoelectric Effect: Work Function, Threshold Frequency and Stopping Potential

By StudyStore · Published 2026-11-05 · 2 min read · 543 words

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The photoelectric effect is the ejection of electrons from a metal surface when light shines on it. It matters because classical wave theory predicted the wrong behavior, and the correct explanation treats light as particles called photons, each carrying energy E = hf.

The key equation

KEmax = hf - φ

Here h is Planck's constant (6.63 × 10-34 J·s), f is the light frequency, and φ is the work function, the minimum energy needed to free an electron from that metal. One photon gives all its energy to one electron. If hf is less than φ, no electron escapes, no matter how many photons arrive.

The threshold frequency is f0 = φ/h. Below it nothing is emitted. Above it, the extra energy becomes kinetic energy of the electron. Using wavelength, E = hc/λ, with hc about 1240 eV·nm.

What the experiment showed

ObservationClassical wave predictionPhoton explanation
A threshold frequency existsAny frequency should work if bright enoughEach photon must individually supply at least φ
KEmax rises with frequencyKE should rise with intensityKE = hf - φ depends on f only
Higher intensity gives more electronsPredictedMore photons means more ejected electrons, same KEmax
Emission is nearly instantShould need time to build up energyOne photon, one electron, no accumulation

The most tested distinction: intensity changes the number of electrons (the current); frequency changes their maximum kinetic energy.

Stopping potential

Reverse the voltage between the plates until the current drops to zero. That voltage is the stopping potential, Vs, and it satisfies

eVs = KEmax

A graph of KEmax against frequency is a straight line. Its slope is h, its x-intercept is f0, and its y-intercept is -φ. The slope is the same for every metal, and only the intercept changes.

Worked example

Sodium has a work function of about 2.3 eV. Light of wavelength 400 nm hits it.

  1. Photon energy: 1240 / 400 = 3.1 eV.
  2. KEmax = 3.1 - 2.3 = 0.8 eV.
  3. Stopping potential: 0.8 V, since the electron charge is one elementary charge.
  4. Threshold wavelength: 1240 / 2.3, about 540 nm. Light of longer wavelength, such as red, ejects nothing.

If the intensity doubles, the current doubles but KEmax and Vs stay 0.8 eV and 0.8 V.

Common traps

  • Thinking brighter light raises electron energy. Only frequency does.
  • Mixing units. Use eV with 1240 eV·nm, or joules with h and f, but not both.
  • Forgetting that KEmax is a maximum. Electrons freed from below the surface lose extra energy.
  • Assuming a lower work function lowers the slope. The slope is always h.

One-minute recap

Photons carry E = hf. An electron leaves only if hf is at least φ, and then KEmax = hf - φ. Frequency sets electron energy, intensity sets electron count, and eVs = KEmax. The KE versus f line has slope h and x-intercept f0.

Check yourself: 5-question mini-quiz

Try each question first, then click it to reveal the answer.

1. Red light fails to eject electrons from a metal. Does making the red light much brighter help?

No. Each photon's energy hf is below the work function, so no single electron can be freed. Only a higher frequency helps.

2. Light with photon energy 5.0 eV hits a metal with work function 3.2 eV. What is the stopping potential?

KE max = 5.0 - 3.2 = 1.8 eV, so the stopping potential is 1.8 V.

3. What does the slope of a KE max versus frequency graph represent?

Planck's constant h, and it is the same for every metal.

4. If light intensity doubles at fixed frequency above threshold, what happens to the photocurrent and KE max?

The photocurrent doubles because twice as many photons eject twice as many electrons, but KE max is unchanged.

5. A metal has a work function of 2.0 eV. What is its threshold wavelength?

1240 / 2.0 = 620 nm. Light of longer wavelength cannot eject electrons.

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Written by StudyStore from standard scientific facts. Study aid only. Always check values against the reference your exam provides.

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